Edu Simulation

Experiment 1: The perpendicular drawn from the center of a circle to a chord bisects the chord.

Figure I

Figure	QR (half chord)	RP (half chord)	Result
(I)	—	—	—
(II)	—	—	—

Conclusion: The perpendicular drawn from the center of a circle to a chord bisects the chord.

Statement: The perpendicular from the center of a circle to a chord bisects the chord.

In the given figure, O is the center of the circle and AB is a chord in which OC ⊥ AB.

AC = BC

S. No.	Statements	S. No.	Reasons
1.	In ΔOCA and ΔOCB	1.	—
(i)	∠OCA = ∠OCB (r)	(i)	Given OC ⊥ AB
(ii)	OA = OB (h)	(ii)	Radius of the same circle
(iii)	OC = OC (s)	(iii)	Common side
2.	ΔOCA ≅ ΔOCB	2.	By RHS theorem
3.	AC = BC	3.	Corresponding sides of congruent triangles

Proved.

Identification and Verification of the Properties of a Circle