Trigonometric
Ratios
📐
Concept
sin, cos & tan
Three ratios, sides explained, SOHCAHTOA.
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📏
Theorem
Pythagoras
h²=p²+b², find each side with the formula.
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✏️
Prove
Prove Identities
Step-by-step proofs: sin²θ+cos²θ=1 and more.
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Figure
Figure Questions
Given a triangle figure, find trig ratios step by step.
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sin, cos & tan
Concept
∠B = 90° (bottom-left) · θ at C (bottom-right)
In right-angled △ABC, ∠B = 90°
∠ACB = θ
is the reference angle at C. Each side is named by its position relative to θ.
h — AC
Hypotenuse (h)
Longest side, opposite the right angle at B. Never touches the 90° corner.
p — AB
Perpendicular (p)
Opposite the reference angle θ. Stands vertically.
b — BC
Base (b)
Adjacent (next to) the reference angle θ. Lies flat at the bottom.
The Three Trigonometric Ratios
sin
Sine — sin θ
Opposite ÷ Hypotenuse
Sides
AB
AC
Letters
p
h
Words
perpendicular
hypotenuse
= opp / hyp
cos
Cosine — cos θ
Adjacent ÷ Hypotenuse
Sides
BC
AC
Letters
b
h
Words
base
hypotenuse
= adj / hyp
tan
Tangent — tan θ
Opposite ÷ Adjacent
Sides
AB
BC
Letters
p
b
Words
perpendicular
base
= opp / adj
Reciprocal Ratios
cosec θ
=
1
sin θ
=
h
p
=
hyp
opp
sec θ
=
1
cos θ
=
h
b
=
hyp
adj
cot θ
=
1
tan θ
=
b
p
=
adj
opp
Memory Trick — SOHCAHTOA
SOH
Sin=Opp/Hyp
CAH
Cos=Adj/Hyp
TOA
Tan=Opp/Adj
S
in=
O
pp/
H
yp |
C
os=
A
dj/
H
yp |
T
an=
O
pp/
A
dj
← Back
Pythagoras' Theorem
Theorem
h
2
= p
2
+ b
2
hypotenuse² = perpendicular² + base²
Right angle at B · θ at C
According to Pythagoras' Theorem:
h² = p² + b²
(Hypotenuse)² = (Perp)² + (Base)²
Therefore, each side:
h
Hypotenuse (h)
h =
√
(p² + b²)
Square root of (p² + b²)
p
Perpendicular (p)
p =
√
(h² − b²)
From h²=p²+b² → p²=h²−b²
b
Base (b)
b =
√
(h² − p²)
From h²=p²+b² → b²=h²−p²
Example:
p=3, b=4 → h=√(9+16)=√25=
5
p=12, h=13 → b=√(169−144)=√25=
5
h = √(p²+b²)
Longest · opposite 90°
p = √(h²−b²)
Vertical · opposite θ
b = √(h²−p²)
Horizontal · adjacent θ
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Figure