✦ Household Expenses · NEB Grade 9
TaxiMeter
TaxiMeter
Simulator
Learn how a taxi meter calculates fare based on distance and waiting time using NBSM-set day and night rates in Nepal.
🚕 4 Modules
📝 3 Examples
✏️ 30+ Questions
🇳🇵 NBSM Rates
📘 Module 01
Introduction
🚕 Real Life Mathematics
How does your taxi meter
calculate the fare?
Taxis in urban areas may or may not be connected with a meter. Metered taxis have uniform fares and very low chances of fraud. Complaints can be filed with the nearest Traffic Police Office with the taxi number. Rates may change over time.
Rs. 14
Initial · Day
Rs. 7.80
Per 200m · Day
Rs. 21
Initial · Night
Rs. 11.70
Per 200m · Night
Initial Charge
Fixed amount charged at the start of every trip. Day: Rs. 14 | Night: Rs. 21. This is the minimum fare regardless of distance.
Distance Fare
Charged every 200 metres. Day: Rs. 7.80 per 200m | Night: Rs. 11.70 per 200m. Always convert km to metres first.
Waiting Charge
Applied when the taxi is idle. Day: Rs. 7.80 per 2 min | Night: Rs. 11.70 per 2 min. Divide rate by 2 then multiply by minutes.
NBSM Taxi Fare Rate Table
| Component | Day Rate (6am – 9pm) | Night Rate (9pm – 6am) |
|---|---|---|
| Initial (minimum) charge | Rs. 14 | Rs. 21 |
| Per 200 metre fare | Rs. 7.80 | Rs. 11.70 |
| Additional fare per kilometre | Rs. 39 | Rs. 58.50 |
| Fare of initial 1 km | Rs. 53 | Rs. 79.50 |
| Waiting charge per 2 minutes | Rs. 7.80 | Rs. 11.70 |
How Is Your Taxi Fare Calculated?
1
Note the Initial Charge
Minimum: Rs. 14 (day) or Rs. 21 (night) — charged at the very start of every trip.
2
Convert Distance to Metres
km × 1000 = metres. Then apply: (rate per 200m ÷ 200) × total metres.
3
Calculate Waiting Charge
(rate per 2 min ÷ 2) × total waiting minutes.
4
Add All Three Components
Total Fare = Initial Charge + Distance Fare + Waiting Charge.
🔢 Module 02
Key Formulas
📐 Master Formula
Total Fare = Initial Charge + Distance Fare + Waiting Charge
All three components always add together to give the final taxi fare.
Distance Fare Formula
Distance Fare =
Rate per 200m
200
× metres
Day: 7.80 200 × metres = 0.039 × metres
Night: 11.70 200 × metres = 0.0585 × metres
Day: 7.80 200 × metres = 0.039 × metres
Night: 11.70 200 × metres = 0.0585 × metres
⚠️ Always convert km → metres first: km × 1000
Waiting Charge Formula
Waiting =
Rate per 2 min
2
× minutes
Day: 7.80 2 × min = 3.90 × minutes
Night: 11.70 2 × min = 5.85 × minutes
Day: 7.80 2 × min = 3.90 × minutes
Night: 11.70 2 × min = 5.85 × minutes
Divide the 2-min rate by 2 to get per-minute rate
Finding Distance from Total
Distance Fare = Total − Initial − Waiting
Distance = Distance Fare Rate per metre
Day: Dist Fare ÷ 0.039
Night: Dist Fare ÷ 0.0585
Distance = Distance Fare Rate per metre
Day: Dist Fare ÷ 0.039
Night: Dist Fare ÷ 0.0585
Reverse-calculate when total fare and waiting are given
Day vs Night at a Glance
Day (6am–9pm)
Initial: Rs. 14
Per metre: Rs. 0.039
Per minute wait: Rs. 3.90
Night (9pm–6am)
Initial: Rs. 21
Per metre: Rs. 0.0585
Per minute wait: Rs. 5.85
Initial: Rs. 14
Per metre: Rs. 0.039
Per minute wait: Rs. 3.90
Night (9pm–6am)
Initial: Rs. 21
Per metre: Rs. 0.0585
Per minute wait: Rs. 5.85
Night rates are 1.5× the day rates
Quick Reference Table
| Component | Day Rate (6am–9pm) | Night Rate (9pm–6am) |
|---|---|---|
| Initial Charge | Rs. 14 | Rs. 21 |
| Per 200m fare | Rs. 7.80 | Rs. 11.70 |
| Per metre fare | Rs. 0.039 | Rs. 0.0585 |
| Per 2 min waiting | Rs. 7.80 | Rs. 11.70 |
| Per minute waiting | Rs. 3.90 | Rs. 5.85 |
| Total for first 1 km | Rs. 53 | Rs. 79.50 |
📝 Module 03
Examples
Example 1 of 3
Bimalakumari took a taxi to travel 6 km from Balkhu to Putalisadak. Initial charge Rs. 14, per 200m Rs. 7.80, waiting 10 minutes at Rs. 7.80 per 2 minutes. How much did she pay?
Distance = 6 kmInitial = Rs. 14Per 200m = Rs. 7.80Waiting = 10 min
✏️ Solution
1
Initial charge = Rs. 14
2
Distance = 6 km = 6000 m
Distance Fare = 7.80200 × 6000 = Rs. 234
Distance Fare = 7.80200 × 6000 = Rs. 234
3
Waiting = 7.802 × 10 = Rs. 39
4
Total = 14 + 234 + 39 = Rs. 287
✅ Total Fare = Rs. 14 + Rs. 234 + Rs. 39 = Rs. 287
Example 2 of 3
Sanjaya pays Rs. 238.50 with 10 min waiting. Initial Rs. 14, per 200m Rs. 7.80, per 2 min Rs. 7.80. Find the distance travelled.
Total = Rs. 238.50Waiting = 10 minInitial = Rs. 14Per 200m = Rs. 7.80
✏️ Solution
1
Waiting = 7.802 × 10 = Rs. 39
2
Distance Fare = 238.50 − 14 − 39 = Rs. 185.50
3
Distance = 185.500.039 ≈ 4756 m ≈ 4.76 km
✅ Distance ≈ 4.76 km
Example 3 of 3
Phaniya pays Rs. 1027.20 with 16 min waiting (night rate). Initial Rs. 21, per 200m Rs. 11.70, per 2 min Rs. 11.70. Find distance.
Total = Rs. 1027.20Waiting = 16 minInitial = Rs. 21Per 200m = Rs. 11.70
✏️ Solution
1
Waiting = 11.702 × 16 = Rs. 93.60
2
Distance Fare = 1027.20 − 21 − 93.60 = Rs. 912.60
3
Distance = 912.600.0585 = 15600 m = 15.6 km
✅ Distance = 15.6 km
✏️ Module 04
Solved Questions
📝 Written Solution
Solution builds here
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