Sum of Cubes · Interactive Explorer
📐
Formula
Full derivation and simplified identity for a³ + b³
🧮
Solve
Step-by-step guided questions to factor expressions
Deriving a³ + b³
start (a + b)³ = a³ + b³ + 3ab(a + b)
or, (a + b)³ = 3ab(a + b) + a³ + b³
or, (a + b)(a + b)² − 3ab(a + b) = a³ + b³
or, (a + b){(a + b)² − 3ab} = a³ + b³ ∵ (a + b) is common on both
or, (a + b)(a² + 2ab + b² − 3ab) = a³ + b³ ∵ using formula of (a + b)²
or, (a + b)(a² − ab + b²) = a³ + b³
(i) a³ + b³ = (a + b)³ − 3ab(a + b)
(ii) a³ + b³ = (a + b)(a² − ab + b²)
8x³ + y³