Theorem 2: The angles on the circumference of a circle, based on the same arc are equal.
Given:
O is the centre of a circle in which inscribed angles ∠ACB and ∠ADB are based on the same arc AB.
Construction: (Click to reveal)
Join centre O of the circle with the points A and B successively.
Proof: (Click to reveal table)
| S. No. | Statements | S. No. | Reasons |
| 1. | ∠AOB = 2∠ACB |
1. | Central angle = 2 × inscribed angle (same arc AB) |
| 2. | ∠AOB = 2∠ADB |
2. | Central angle = 2 × inscribed angle (same arc AB) |
| 3. | 2∠ACB = 2∠ADB or, ∠ACB = ∠ADB |
3. | From (1) and (2) |
Proved.
∴ The angles on the circumference of a circle, based on the same arc are equal.