Theorem: The opposite angles of a cyclic quadrilateral are supplementary (sum to 180°).
Given:
O is the centre of the circle. ABCD is a cyclic quadrilateral where all vertices lie on the circumference.
To prove:
∠ABC + ∠ADC = 180°
∠BCD + ∠BAD = 180°
Construction: (Click to reveal)
Join points A and C to the center O (Draw OA and OC).
Proof: (Click to reveal table)
| S.N. | Statements | S.N. | Reasons |
| 1. | Obtuse ∠AOC = 2∠ADC |
1. | Central angle is double the inscribed angle on the same arc ABC. |
| 2. | Reflex ∠AOC = 2∠ABC |
2. | Central angle is double the inscribed angle on the same arc ADC. |
| 3. | Obtuse ∠AOC + Reflex ∠AOC = 2∠ADC + 2∠ABC |
3. | Adding statement (1) and (2). |
| 4. | 360° = 2(∠ADC + ∠ABC) |
4. | The sum of angles around a point (O) is 360°. |
| 5. | ∴ ∠ABC + ∠ADC = 180° |
5. | Dividing both sides by 2. |
Proved.
Similarly, we can prove ∠BCD + ∠BAD = 180°.