Consider a cone with vertex A. Let OB = r cm be the radius of the base of the cone.
Join A to O (the centre of the base). Then, AO is the height of the cone, i.e., AO = h.
AC and AB are the slant heights of the cone, i.e., AC = AB = l.
The slant height of a cone of radius r and height h is equal to √(h² + r²).
Take a cone made from a paper. Cut it as its slant surface and open it as shown in the Figure. Now, the curved surface of cone is transferred to the flat form as shown in the Figure, which is a sector. And the length of this sector is equal to the circumference of the circular base of the cone.
Now, cut the sector into 4 equal pieces as shown in the Figure (ii) and color two pieces with red.
Then, arrange two small sectors in the same directions and remaining two in opposite directions as shown in figure (iii).
Here,
If the radius of base of the cone is 'r', slant height is 'ℓ' and the vertical height is 'h', then,
Curved surface area of the cone (CSA) = πr² + πrℓ
Total surface area of the cone (TSA) = Area of base + Curved surface area (CSA)
Total surface area (TSA) = πr² + πrℓ
Total surface area (TSA) = πr(r + ℓ) sq. unit
Explore how the volume of a cone relates to a cylinder with the same base radius and height.
Fill the cone with sand or dust of soil and pour it into the cylinder until it is filled up completely.
Since 3 full cones fill exactly 1 cylinder of equal dimensions:
A cone is a three-dimensional geometric shape formed by rotating a right-angled triangle around one of its sides (the axis).
It has a circular base and a pointed apex. The net of a cone consists of:
1. A circular base — the flat bottom of the cone
2. A circular sector — the curved lateral surface when unfolded
By adjusting the slider below, you can see how the cone folds and unfolds to reveal its net.